python(leetcode)-344

编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
 
示例 1：

输入：["h","e","l","l","o"]
输出：["o","l","l","e","h"]
示例 2：

输入：["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]

 1 class Solution:
 2     def reverseString(self, s):
 3         """
 4         :type s: List[str]
 5         :rtype: void Do not return anything, modify s in-place instead.
 6         """
 7         s[:]=s[::-1]
 8 
 9 if __name__=="__main__":
10     s=Solution()
11     list = [1,2,3]
12     print(s.reverseString(list))

 1 class Solution:
 2     def reverseString(self, s):
 3         """
 4         :type s: List[str]
 5         :rtype: void Do not return anything, modify s in-place instead.
 6         """
 7         for i in range(len(s) // 2):
 8             temp = s[i]
 9             s[i] = s[-i - 1]
10             s[-i - 1] = temp
11 
12 if __name__=="__main__":
13     s=Solution()
14     list = [1,2,3]
15     print(s.reverseString(list))