Java 正则表达式匹配xml节点

<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE mapper PUBLIC "-//mybatis.org//DTD Mapper 3.0//EN" "http://mybatis.org/dtd/mybatis-3-mapper.dtd" >
<mapper namespace="com.test.dao.sysResourcesMapper" >
   
    <resultMap id="BaseResultMap" type="com.zh.car.entity.SysResources" >
        <id column="id" property="id"/>
        <result column="alias" property="alias" jdbcType="VARCHAR" />
        <result column="name" property="name" jdbcType="VARCHAR" />
        <result column="parent_id" property="parentId" jdbcType="VARCHAR" />
        <result column="url" property="url" jdbcType="VARCHAR" />
        <result column="sort" property="sort" jdbcType="INTEGER" />
        <result column="icon_cls" property="iconCls" jdbcType="VARCHAR" />
        <result column="rules" property="rules" jdbcType="VARCHAR" />
        <result column="create_time" property="createTime" jdbcType="TIMESTAMP" />
    </resultMap>
    <sql id="Base_Column_List" >
    id,alias,name,parent_id,url,sort,icon_cls,rules,create_time
    </sql>
</mapper>
正则表达式：Pattern pattern = Pattern.compile("<resultMap\s+id=\"BaseResultMap\"[\s\S]+?>([\s\S]+?)</resultMap>");
Matcher m = pattern.matcher(xml);
if (m.find()) {
    System.out.println(m.group());
}输出：<resultMap id="BaseResultMap" type="com.test.entity.SysResources" >
        <id column="id" property="id"/>
        <result column="alias" property="alias" jdbcType="VARCHAR" />
        <result column="name" property="name" jdbcType="VARCHAR" />
        <result column="parent_id" property="parentId" jdbcType="VARCHAR" />
        <result column="url" property="url" jdbcType="VARCHAR" />
        <result column="sort" property="sort" jdbcType="INTEGER" />
        <result column="icon_cls" property="iconCls" jdbcType="VARCHAR" />
        <result column="rules" property="rules" jdbcType="VARCHAR" />
        <result column="create_time" property="createTime" jdbcType="TIMESTAMP" />
    </resultMap>如果是要获取resultMap里面的节点：
Pattern pattern = Pattern.compile("<resultMap\s+id=\"BaseResultMap\"[\s\S]+?>([\s\S]+?)</resultMap>");
Matcher m = pattern.matcher(xml);
if (m.find()) {
    System.out.println(m.group(1));
}