LeetCode 1389. 按既定顺序创建目标数组

示例 1：

输入：nums = [0,1,2,3,4], index = [0,1,2,2,1]
输出：[0,4,1,3,2]
解释：
nums index target
0 0 [0]
1 1 [0,1]
2 2 [0,1,2]
3 2 [0,1,3,2]
4 1 [0,4,1,3,2]
示例 2：

输入：nums = [1,2,3,4,0], index = [0,1,2,3,0]
输出：[0,1,2,3,4]
解释：
nums index target
1 0 [1]
2 1 [1,2]
3 2 [1,2,3]
4 3 [1,2,3,4]
0 0 [0,1,2,3,4]
示例 3：

输入：nums = [1], index = [0]
输出：[1]

package Array;

import java.util.ArrayList;

/**
 * Created with IntelliJ IDEA.
 * Version : 1.0
 * Author  : cunyu
 * Email   : cunyu1024@foxmail.com
 * Website : https://cunyu1943.github.io
 * Date    : 2020/3/26 10:55
 * Project : LeetCode
 * Package : Array
 * Class   : OneThreeEightNine
 * Desc    : 1389. 按既定顺序创建目标数组
 */
public class OneThreeEightNine {
	public static void main(String[] args) throws Exception {
		OneThreeEightNine oneThreeEightNine = new OneThreeEightNine();
		int[] nums = {0, 1, 2, 3, 4};
		int[] index = {0, 1, 2, 2, 1};
		for (int item : oneThreeEightNine.createTargetArray(nums, index)
		) {
			System.out.println(item);
		}
	}

	public int[] createTargetArray(int[] nums, int[] index) {
		ArrayList<Integer> list = new ArrayList<>();
		for (int i = 0; i < nums.length;i++){
			list.add(index[i],nums[i]);
		}

		int[] target = new int[nums.length];
		for (int i = 0; i < list.size(); i++) {
			target[i] = list.get(i);
		}
		return target;
	}
}