HttpClient来自官方的JSON扩展方法

原创

HueiFeng

修改于 2020-04-13 11:15:46

1.2K0

修改于 2020-04-13 11:15:46

文章被收录于专栏：HueiFeng技术专栏HueiFeng技术专栏

System.Net.Http.Json

Json的序列化和反序列化是我们日常常见的操作，通过System.Net.Http.Json我们可以用少量的代码实现上述操作.正如在github设计文档中所描述

Serializing and deserializing JSON payloads from the network is a very

common operation for clients, especially in the upcoming Blazor

environment. Right now, sending a JSON payload to the server requires

multiple lines of code, which will be a major speed bump for those

customers. We'd like to add extension methods on top of HttpClient that

allows doing those operations with a single method call.

他的依赖项也非常的少目前只依赖System.Net.Http, System.Text.Json

System.Text.Json相对于Newtonsoftjson平均快了两倍，如果有兴趣相关基准测试可在这个文章中查阅

https://devblogs.microsoft.com/dotnet/try-the-new-system-text-json-apis/

在.NET中安装和使用

目前它还是预览版本

dotnet add package System.Net.Http.Json

public static async Task<Customer> GetCustomerAsync()
{
    HttpClient clinet=new HttpClient();
    var request = new HttpRequestMessage(HttpMethod.Get, "http://localhost:5000/customers");
    var response = await clinet.SendAsync(request);
    return await response.Content.ReadFromJsonAsync<Customer>();
}

通过ReadFromJsonAsync直接可以反序列化

public static async Task<Customer> CreateCustomerAsync()
{
    HttpClient clinet = new HttpClient();
    var customer=new Customer()
    {
        Id = "1",
        Name = "Fh"
    };
    var request = new HttpRequestMessage(HttpMethod.Post, "http://localhost:5000/create");
    request.Content = JsonContent.Create(customer);
    var response = await clinet.SendAsync(request);
    var content=response.Content.ReadAsStringAsync();
    return customer;
}

还可以以下面这种简洁方式使用

_client.GetFromJsonAsync<IReadOnlyList<Customer>>("/customers");
_client.GetFromJsonAsync<Customer?>($"/customers/{id}");
_client.PutAsJsonAsync($"/customers/{customerId}", customer);

if (response.IsSuccessStatusCode)
{
    try
    {
        return await response.Content.ReadFromJsonAsync<User>();
    }
    catch (NotSupportedException) // When content type is not valid
    {
        Console.WriteLine("The content type is not supported.");
    }
    catch (JsonException) // Invalid JSON
    {
        Console.WriteLine("Invalid JSON.");
    }
}

还可以通过NotSupportedException和JsonException异常类处理相应的异常.