10个Python基础快速进阶技巧

my_string = "ABCDE"reversed_string = my_string[::-1]print(reversed_string)
# Output# EDCBA

my_string = "my name is chaitanya baweja"new_string = my_string.title()print(new_string)
# Output# My Name Is Chaitanya Baweja

a = 1b = 2
a, b = b, a
print(a) # 2print(b) # 1

dict_1 = {'apple': 9, 'banana': 6}dict_2 = {'banana': 4, 'orange': 8}combined_dict = {**dict_1, **dict_2}print(combined_dict)# Output# {'apple': 9, 'banana': 4, 'orange': 8}

num = 123456list_of_digits = list(map(int, str(num)))print(list_of_digits)# [1, 2, 3, 4, 5, 6]
list_of_digits = [int(x) for x in str(num)]print(list_of_digits)# [1, 2, 3, 4, 5, 6]

def unique(l):    if len(l)==len(set(l)):        print("All elements are unique")    else:        print("List has duplicates")
unique([1,2,3,4])# All elements are unique
unique([1,1,2,3])# List has duplicates

string_1 = "My name is Chaitanya Baweja"string_2 = "sample/ string 2"
print(string_1.split())# ['My', 'name', 'is', 'Chaitanya', 'Baweja']
print(string_2.split('/'))# ['sample', ' string 2']

my_string = "abcba"
if my_string == my_string[::-1]:    print("palindrome")else:    print("not palindrome")
# Output# palindrome

from collections import Counter
my_list = ['a','a','b','b','b','c','d','d','d','d','d']count = Counter(my_list) # defining a counter object
print(count) # Of all elements# Counter({'d': 5, 'b': 3, 'a': 2, 'c': 1})
print(count['b']) # of individual element# 3
print(count.most_common(1)) # most frequent element# [('d', 5)]

my_list = ['a', 'b', 'c', 'd', 'e']
for index, value in enumerate(my_list):    print('{0}: {1}'.format(index, value))
# 0: a# 1: b# 2: c# 3: d# 4: e