搞定二叉树的查找

class BinaryTree {
	private HeroNode root;
	
	public void setRoot(HeroNode root) {
		this.root = root;
	}
	
	//前序查找
	public HeroNode preOrderSearch(int no) {
		if (root != null) {
			return root.preOrderSearch(no);
		} else {
			return null;
		}
	}
	
	public HeroNode infixOrderSearch(int no) {
		if (root != null) {
			return root.infixOrderSearch(no);
		} else {
			return null;
		}
	}
	
	public HeroNode postOrderSearch(int no) {
		if (root != null) {
			return root.postOrderSearch(no);
		} else {
			return null;
		}
	}
	
}

class HeroNode {
	private int no;
	private String name;
	private HeroNode left;
	private HeroNode right;
	
	public HeroNode(int no, String name) {
		this.no = no;
		this.name = name;
	}
	
	public int getNo() {
		return no;
	}
	
	public void setNo(int no) {
		this.no = no;
	}
	
	public String getName() {
		return name;
	}
	
	public void setName(String name) {
		this.name = name;
	}
	
	public HeroNode getLeft() {
		return left;
	}
	
	public void setLeft(HeroNode left) {
		this.left = left;
	}
	
	public HeroNode getRight() {
		return right;
	}
	
	public void setRight(HeroNode right) {
		this.right = right;
	}
	
	@Override
	public String toString() {
		return "HearNode{" +
				"no=" + no +
				", name='" + name + '\'' +
				'}';
	}
	
	//前序查找
	public HeroNode preOrderSearch(int no) {
		if (this.no == no) {
			return this;
		}
		
		HeroNode resNode = null;
		if (this.left != null) {
			resNode = this.left.preOrderSearch(no);
		}
		if (resNode != null) {
			return resNode;
		}
		
		/*
		1.左递归前序查找，找到节点就返回，否则继续判断
		2. 当前节点的右子节点是否为空如果不为空则继续
		 */
		if (this.right != null) {
			resNode = this.right.preOrderSearch(no);
		}
		return resNode;
	}
	
	//中序查找
	public HeroNode infixOrderSearch(int no) {
		HeroNode resNode = null;
		if (this.left != null) {
			resNode = this.left.preOrderSearch(no);
		}
		if (resNode != null) {
			return resNode;
		}
		
		if (this.no == no) {
			return this;
		}
		
		if (this.right != null) {
			resNode = this.right.preOrderSearch(no);
		}
		return resNode;
	}
	
	//后序查找
	public HeroNode postOrderSearch(int no) {
		HeroNode resNode = null;
		if (this.left != null) {
			resNode = this.left.preOrderSearch(no);
		}
		if (resNode != null) {
			return resNode;
		}
		
		if (this.right != null) {
			resNode = this.right.preOrderSearch(no);
		}
		if (resNode != null) {
			return resNode;
		}
		
		if (this.no == no) {
			return this;
		}
		return resNode;
	}
}