在老式手机上,用户通过数字键盘输入,手机将提供与这些数字相匹配的单词列表。 每个数字映射到0至4个字母。给定一个数字序列,实现一个算法来返回匹配单词的列表。 你会得到一张含有有效单词的列表。映射如下图所示:
示例 1:
输入: num = "8733", words = ["tree", "used"]
输出: ["tree", "used"]
示例 2:
输入: num = "2", words = ["a", "b", "c", "d"]
输出: ["a", "b", "c"]
提示:
num.length <= 1000
words.length <= 500
words[i].length == num.length
num中不会出现 0, 1 这两个数字
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/t9-lcci 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
类似题目:LeetCode 17. 电话号码的字母组合(回溯)
class Solution {
public:
vector<string> getValidT9Words(string num, vector<string>& words) {
string key[10] = {"","","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"};
vector<string> ans;
int i;
bool ok;
for(auto& w : words)
{
ok = true;
for(i = 0; i < w.size(); ++i)
{
if(key[num[i]-'0'].find(w[i]) == string::npos)
{
ok = false;
break;
}
}
if(ok)
ans.push_back(w);
}
return ans;
}
};
36 ms 12.2 MB
class Solution {
public:
vector<string> getValidT9Words(string num, vector<string>& words) {
char ch[26] = {'2', '2', '2', '3', '3', '3', '4', '4', '4',
'5', '5', '5', '6', '6', '6', '7', '7', '7', '7',
'8', '8', '8', '9', '9', '9', '9'};
vector<string> ans;
int i;
bool ok;
for(auto& w : words)
{
ok = true;
for(i = 0; i < w.size(); ++i)
{
if(num[i] != ch[w[i]-'a'])
{
ok = false;
break;
}
}
if(ok)
ans.push_back(w);
}
return ans;
}
};
28 ms 12 MB