LeetCode 5472. 重新排列字符串

**输入：**s = "codeleet", `indices` = [4,5,6,7,0,2,1,3]
**输出：**"leetcode"
**解释：**如图所示，"codeleet" 重新排列后变为 "leetcode" 。

**示例 2：**

**输入：**s = "abc", `indices` = [0,1,2]
**输出：**"abc"
**解释：**重新排列后，每个字符都还留在原来的位置上。

**示例 3：**

**输入：**s = "aiohn", `indices` = [3,1,4,2,0]
**输出：**"nihao"

**示例 4：**

**输入：**s = "aaiougrt", `indices` = [4,0,2,6,7,3,1,5]
**输出：**"arigatou"

**示例 5：**

**输入：**s = "art", `indices` = [1,0,2]
**输出：**"rat"

class Solution:
    def restoreString(self, s: str, indices: [int]) -> str:
        tempList = [""]*len(indices)
        strList = list(s)
        for idx,val in enumerate(indices):
            tempStr = strList[idx]
            tempList[val] = tempStr
        # print(tempList)
        return "".join(tempList)