A = [23 42 37 15 52];
M = min(A)
M =
15
A = [-2+2i 4+i -1-3i];
min(A)
ans =
-2.0000 + 2.0000i
A = [2 8 4; 7 3 9]
A =
2 8 4
7 3 9
M = min(A)
M =
2 3 4
A = [1.7 1.2 1.5; 1.3 1.6 1.99]
A =
1.7000 1.2000 1.5000
1.3000 1.6000 1.9900
M = min(A,[],2)
M =
1.2000
1.3000
A = [1 9 -2; 8 4 -5]
A =
1 9 -2
8 4 -5
[M,I] = min(A)
M =
1 4 -5
I =
1 2 2
A = [1 7 3; 6 2 9]
A =
1 7 3
6 2 9
B = 5;
C = min(A,B)
C =
1 5 3
5 2 5
A = [8 2 4; 7 3 9]
A =
8 2 4
7 3 9
A(:)
ans =
8
7
2
3
4
9
[M,I] = min(A(:))
M =
2
I =
3
[I_row, I_col] = ind2sub(size(A),I)
I_row =
1
I_col =
2
M = min(min(A))
M =
2
创建一个向量并计算它的最小值,不包括NaN值
A = [1.77 -0.005 3.98 -2.95 NaN 0.34 NaN 0.19];
M = min(A,[],'omitnan')
M =
-2.9500
min(A)也会产生这个结果,因为'omitnan'是默认选项 使用“includes enan”标志返回NaN
M = min(A,[],'includenan')
M =
NaN