leetcode: explore-strings-32 反转字符串

Write a function that reverses a string. The input string is given as an array of characters char[].

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

You may assume all the characters consist of printable ascii characters.



Example 1:

Input: ["h","e","l","l","o"]
Output: ["o","l","l","e","h"]
Example 2:

Input: ["H","a","n","n","a","h"]
Output: ["h","a","n","n","a","H"]

class Solution(object):
    def reverseString(self, s):
        """
        :type s: List[str]
        :rtype: None Do not return anything, modify s in-place instead.
        """
        s.reverse()

s = [1, 2, 3]
# 原地修改，没有返回值
s.reverse()

# 返回新的 list
s = reversed(s)

# 特别注意切片的方式，十分灵活，也用得比较多
s = s[::-1]

s = [1, 2, 3]
s = "".join(s)
s = list(s)

s = "1,2,3"
s = s.split(",")