前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >LinkedList - 25. Reverse Nodes in k-Group

LinkedList - 25. Reverse Nodes in k-Group

作者头像
ppxai
发布2020-09-23 17:22:46
3610
发布2020-09-23 17:22:46
举报
文章被收录于专栏:皮皮星球皮皮星球

25. Reverse Nodes in k-Group

Given a linked list, reverse the nodes of a linked list k at a time and return its modified list.

k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is.

Example:

Given this linked list: 1->2->3->4->5

For k = 2, you should return: 2->1->4->3->5

For k = 3, you should return: 3->2->1->4->5

Note:

  • Only constant extra memory is allowed.
  • You may not alter the values in the list's nodes, only nodes itself may be changed.

思路:

题目意思是每k个节点翻转一次链表,如果节点不足k个,就不翻转,这是一个简单的实现题,运用递归的思想,找到翻转链表的起始点,然后翻转k个节点。

代码:

java:

代码语言:javascript
复制
/**

 * Definition for singly-linked list.

 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
class Solution {
    public ListNode reverseKGroup(ListNode head, int k) {
        if (head == null || head.next == null) return head;
        
        int count = 0;
        ListNode cur = head;
        while (cur != null && count != k) {
            cur = cur.next;
            count++;
        }
        
        if (count == k) {
            cur = reverseKGroup(cur, k);
            // resever list
            while (count-- > 0) {
                ListNode tmp = head.next;
                head.next = cur;
                cur = head;
                head = tmp;
            }
            head = cur;
        }
        
        return head;
    }
}
本文参与 腾讯云自媒体分享计划,分享自作者个人站点/博客。
原始发表:2019年07月27日,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体分享计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档