1027 Colors in Mars (20 分)
People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red
, the middle 2 digits for Green
, and the last 2 digits for Blue
. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.
Each input file contains one test case which occupies a line containing the three decimal color values.
For each test case you should output the Mars RGB value in the following format: first output #
, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0
to its left.
15 43 71
#123456
题意:三个十进制的数,把它们转换为十三进制的数输出。
分析:因为0~168的十进制转换为13进制最多两位,个位是x%13,十位是x/13,20分水题~
// luogu-judger-enable-o2
#include<bits/stdc++.h>
#include<unordered_set>
#define rg register ll
#define inf 2147483647
#define min(a,b) (a<b?a:b)
#define max(a,b) (a>b?a:b)
#define ll long long
#define maxn 300005
#define lb(x) (x&(-x))
const double eps = 1e-6;
using namespace std;
inline ll read()
{
char ch = getchar(); ll s = 0, w = 1;
while (ch < 48 || ch>57) { if (ch == '-')w = -1; ch = getchar(); }
while (ch >= 48 && ch <= 57) { s = (s << 1) + (s << 3) + (ch ^ 48); ch = getchar(); }
return s * w;
}
inline void write(ll x)
{
if (x < 0)putchar('-'), x = -x;
if (x > 9)write(x / 10);
putchar(x % 10 + 48);
}
ll a,b,c;
char s[20]="0123456789ABC";
inline void f(ll x)
{
if(x<=12)
{
cout<<0<<s[x];
return ;
}
cout<<s[x/13]<<s[x%13];
return ;
}
int main()
{
cin>>a>>b>>c;
cout<<"#";
f(a),f(b),f(c);
return 0;
}