c#任意进制转换
开发人员通常需要将十进制数转换为二进制、八进制、十六进制或其他进制。由于这是一个常见的任务，在互联网上有很多例子是如何做到的。你可以很容易地找到很多十进制到二进制，十进制到八进制，十进制到十六进制，等等，但是很难找到一个更通用的转换器，可以转换一个十进制数到任何其他进制。这就是我在这篇文章中要向你们展示的。该实现方法可以将任意十进制数转换为2到36进制的任意进制。
long number = 123456789;
Console.WriteLine("Decimal: " + number.ToString());
Console.WriteLine("Binary : " + DecimalToArbitrarySystem(number, 2));
Console.WriteLine("Octal : " + DecimalToArbitrarySystem(number, 8));
Console.WriteLine("Hex : " + DecimalToArbitrarySystem(number, 16));
Console.WriteLine("Base 36: " + DecimalToArbitrarySystem(number, 36));
// This example displays the following output:
// Decimal: 123456789
// Binary : 111010110111100110100010101
// Octal : 726746425
// Hex : 75BCD15
// Base 36: 21I3V9以下是该方法的实现：
/// <summary>
/// Converts the given decimal number to the numeral system with the
/// specified radix (in the range [2, 36]).
/// </summary>
/// <param name="decimalNumber">The number to convert.</param>
/// <param name="radix">The radix of the destination numeral system
/// (in the range [2, 36]).</param>
/// <returns></returns>
public static string DecimalToArbitrarySystem(long decimalNumber, int radix)
{
const int BitsInLong = 64;
const string Digits = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
if (radix < 2 || radix > Digits.Length)
throw new ArgumentException("The radix must be >= 2 and <= " +
Digits.Length.ToString());
if (decimalNumber == 0)
return "0";
int index = BitsInLong - 1;
long currentNumber = Math.Abs(decimalNumber);
char[] charArray = new char[BitsInLong];
while (currentNumber != 0)
{
int remainder = (int)(currentNumber % radix);
charArray[index--] = Digits[remainder];
currentNumber = currentNumber / radix;
}
string result = new String(charArray, index + 1, BitsInLong - index - 1);
if (decimalNumber < 0)
{
result = "-" + result;
}
return result;
}本文参与 腾讯云自媒体分享计划，分享自作者个人站点/博客。
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