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社区首页 >专栏 >CodeForces - 1047A

CodeForces - 1047A

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风骨散人Chiam
发布2020-10-28 10:36:37
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发布2020-10-28 10:36:37
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文章被收录于专栏:CSDN旧文

A. Little C Loves 3 I time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output Little C loves number «3» very much. He loves all things about it.

Now he has a positive integer n. He wants to split n into 3 positive integers a,b,c, such that a+b+c=n and none of the 3 integers is a multiple of 3. Help him to find a solution.

Input A single line containing one integer n (3≤n≤109) — the integer Little C has.

Output Print 3 positive integers a,b,c in a single line, such that a+b+c=n and none of them is a multiple of 3.

It can be proved that there is at least one solution. If there are multiple solutions, print any of them.

Examples inputCopy 3 outputCopy 1 1 1 inputCopy 233 outputCopy 77 77 79

签到题,读遍题,就能过!

代码语言:javascript
复制
#include<bits/stdc++.h>
using namespace std;
int main(){
    int n;
    cin>>n;
    int a;
     a=n/3;
    if(a%3==0){ if(n%3==0) cout<<a-2<<' '<<a+1<<' '<<a+1;
                else if(n%3==1) cout<<a-1<<' '<<a+1<<' '<<a+1;
                else cout<<a-1<<' '<<a+1<<' '<<a+2;}
    if(a%3==1){
        if(n%3==0) cout<<a<<' '<<a<<' '<<a;
        if(n%3==1) cout<<a<<' '<<a<<' '<<a+1;
        if(n%3==2) cout<<a+1<<' '<<a+1<<' '<<a;

    }
    if(a%3==2)
    {
        if(n%3==0) cout<<a<<' '<<a<<' '<<a;
        if(n%3==1) cout<<a-1<<' '<<a+2<<' '<<a;
        if(n%3==2) cout<<a<<' '<<a<<' '<<a+2;
    }
    return 0;
}
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原始发表:2019/05/23 ,如有侵权请联系 cloudcommunity@tencent.com 删除

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