题目要求: 请实现一个函数,把字符串 s 中的每个空格替换成"%20"。
示例 1:
输入:s = “We are happy.” 输出:“We%20are%20happy.”
限制:
0 <= s 的长度 <= 10000
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/ti-huan-kong-ge-lcof
解题思路: C++字符串替换函数replace。。。
通关代码:
class Solution {
public:
string replaceSpace(string s) {
for (int pos = s.find(" "); pos != s.npos; pos = s.find(" ")) {
s.replace(pos, 1, "%20");
}
return s;
}
};
通关截图: