Codeforce 1311A Add Odd or Subtract Even

Add Odd or Subtract Even time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output You are given two positive integers a and b.

In one move, you can change a in the following way:

Choose any positive odd integer x (x>0) and replace a with a+x; choose any positive even integer y (y>0) and replace a with a−y. You can perform as many such operations as you want. You can choose the same numbers x and y in different moves.

Your task is to find the minimum number of moves required to obtain b from a. It is guaranteed that you can always obtain b from a.

You have to answer t independent test cases.

Input The first line of the input contains one integer t (1≤t≤104) — the number of test cases.

Then t test cases follow. Each test case is given as two space-separated integers a and b (1≤a,b≤109).

Output For each test case, print the answer — the minimum number of moves required to obtain b from a if you can perform any number of moves described in the problem statement. It is guaranteed that you can always obtain b from a.

Example input 5 2 3 10 10 2 4 7 4 9 3 output 1 0 2 2 1 Note In the first test case, you can just add 1.

In the second test case, you don’t need to do anything.

In the third test case, you can add 1 two times.

In the fourth test case, you can subtract 4 and add 1.

In the fifth test case, you can just subtract 6. 分差的奇偶性，和大小

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int t;
    cin >> t;
    while (t--)
    {
    
        int a,b,c;
        cin>>a>>b;
        if(a==b) cout<<0<<endl;
        else if(a>b)
        {
            if((a-b)%2==0)cout<<1<<endl;
            else cout<<2<<endl;
        }
        else {
 
            if((b-a)%2==0)cout<<2<<endl;
            else cout<<1<<endl;
        }
    }
}