HDOJ(HDU) 1562 Guess the number(水题，枚举就行)

谙忆

发布于 2021-01-21 15:23:22

1910

发布于 2021-01-21 15:23:22

Problem Description Happy new year to everybody! Now, I want you to guess a minimum number x betwwn 1000 and 9999 to let (1) x % a = 0; (2) (x+1) % b = 0; (3) (x+2) % c = 0; and a, b, c are integers between 1 and 100. Given a,b,c, tell me what is the number of x ?

Input The number of test cases c is in the first line of input, then c test cases followed.every test contains three integers a, b, c.

Output For each test case your program should output one line with the minimal number x, you should remember that x is between 1000 and 9999. If there is no answer for x, output “Impossible”.

Sample Input 2 44 38 49 25 56 3

Sample Output Impossible 2575

枚举就可以了。。

import java.util.Scanner;

public class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while (t-- > 0) {
            int a = sc.nextInt();
            int b = sc.nextInt();
            int c = sc.nextInt();
            boolean is = true;
            int tm=a;
            while(a<1000){
                a=a+tm;
            }

            //注意！答案的范围是[1000,9999]
            for (int i = a; i < 10000; i = i + tm) {
                //此处注意i是加tm，而不是再加a了，因为a可能变了。
                if ((i+1)%b==0&&(i+2)%c==0) {
                    System.out.println(i);
                    is = false;
                    break;
                }
            }

            if (is) {
                System.out.println("Impossible");
            }

        }
    }

}

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原始发表：2016/04/18 ，如有侵权请联系 cloudcommunity@tencent.com 删除

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