给你链表的头节点 head 和一个整数 k 。
交换 链表正数第 k 个节点和倒数第 k 个节点的值后,返回链表的头节点(链表 从 1 开始索引)。
示例 1:
输入:head = [1,2,3,4,5], k = 2
输出:[1,4,3,2,5]
示例 2:
输入:head = [7,9,6,6,7,8,3,0,9,5], k = 5
输出:[7,9,6,6,8,7,3,0,9,5]
示例 3:
输入:head = [1], k = 1
输出:[1]
示例 4:
输入:head = [1,2], k = 1
输出:[2,1]
示例 5:
输入:head = [1,2,3], k = 2
输出:[1,2,3]
提示:
链表中节点的数目是 n
1 <= k <= n <= 10^5
0 <= Node.val <= 100
https://leetcode-cn.com/problems/swapping-nodes-in-a-linked-list/
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* swapNodes(ListNode* head, int k) {
ListNode* cur = head, *prev = head;
ListNode* a, *b;
int n = k-1;
while(n--)
{
cur = cur->next;
}
a = cur;
while(cur->next != NULL)
{
cur = cur->next;
prev = prev->next;
}
b = prev;
swap(a->val, b->val);
return head;
}
};
1108 ms 176.3 MB C++