# len:获取元组的长度
t = (1,2,3,4,5)
len(t)
5
# max,min:最大最小值
print(max(t))
print(min(t))
5
1
# tuple:转化或创建元组
l = (1,2,3,4,5)
t = tuple(l)
print(t)
t = tuple()
print(t)
(1, 2, 3, 4, 5)
()
# count:计算指定数据出现的次数
t = (2,1,2,3,45,1,1,2,)
print(t.count(2))
# index:求指定元素在元组中的索引位置
print(t.index(45))
# 如果需要的查找的数字是多个,则返回第一个
print(t.index(1))
3
4
1
# 两个变量交换值
a = 1
b = 3
print(a)
print(b)
print("*" * 20)
# java程序员会这么写:
c = a
a = b
b = c
print(a)
print(b)
print("*" * 20)
# python写法
a,b = b,a
print(a)
print(b)
1
3
********************
3
1
********************
1
3
# 集合的定义
s = set()
print(type(s))
print(s)
# 此时,大括号内一定要有值,否则定义出的是一个dict
s = {1,2,3,4,5,6,7}
print(type(s))
print(s)
<class 'set'>
set()
<class 'set'>
{1, 2, 3, 4, 5, 6, 7}
# 如果只是用大括号定义,则定义的是一个dict类型
d = {}
print(type(d))
print(d)
<class 'dict'>
{}
# 成员检测
# in,not in
s = {4,5,"i", "love", "you"}
print(s)
if "love" in s:
print("Yes")
if "haha" not in s:
print("Yes")
{'you', 4, 5, 'love', 'i'}
Yes
Yes
# for 循环
s = {4,5,"i", "love", "you"}
for i in s:
print(i)
you
4
5
love
i
# 带有元组的集合遍历
s = {(1,2,3,), ("i", "love", "you"), (4,5,6)}
for k,m,n in s:
print(k, "--", m, "--", n)
for k in s:
print(k)
i -- love -- you
4 -- 5 -- 6
1 -- 2 -- 3
('i', 'love', 'you')
(4, 5, 6)
(1, 2, 3)
# 普通集合内涵
# 以下集合在初始化后自动过滤掉重复元素
s = {23,223,233,2,4,5,6,3,4,1,5,3}
print(s)
# 普通集合内涵
ss = {i for i in s}
print(ss)
{1, 2, 3, 4, 5, 6, 233, 23, 223}
{1, 2, 3, 4, 5, 6, 233, 23, 223}
# 带条件的集合内涵
sss = {i for i in s if i % 2 == 0}
print(sss)
{2, 4, 6}
# 多循环的集合内涵
s1 = {1,2,3,4}
s2 = {"i", "love", "you"}
s = {m*n for m in s2 for n in s1}
print(s)
s = {m*n for m in s2 for n in s1 if n == 2}
print(s)
{'you', 'youyou', 'love', 'lovelovelovelove', 'lovelovelove', 'lovelove', 'iii', 'youyouyouyou', 'ii', 'i', 'iiii', 'youyouyou'}
{'lovelove', 'youyou', 'ii'}
# len,max,min:跟其他基本的函数一致
s = {23,54,72,3,5,3,3,6,1,543}
print(len(s))
print(max(s))
print(min(s))
8
543
1
# set:生成一个集合
l = {1,2,3,4,5,4,3,2,1}
s = set(l)
print(s)
{1, 2, 3, 4, 5}
# add:向集合内添加元素
s = {1}
s.add(3)
print(s)
{1, 3}
# clear
s = {1,2,3,4,5}
print(id(s))
s.clear()
print(id(s))
# 结果表明clear函数是原地清空数据
1370773843528
1370773843528
# copy:拷贝
# remove:移除指定的值,直接改变原有值,如果要删除的值不存在,报错
# discard:移除集合中指定的值跟remove一样,但是如果要删除的话,不报错
s = {23,4,3,5,1,2,3}
s.remove(4)
print(s)
s.discard(1)
print(s)
print("*" * 20)
s.discard(100)
print(s)
s.remove(100)
print(s)
{1, 2, 3, 5, 23}
{2, 3, 5, 23}
********************
{2, 3, 5, 23}
---------------------------------------------------------------------------
KeyError Traceback (most recent call last)
<ipython-input-35-0113522ad176> in <module>
12 print(s)
13
---> 14 s.remove(100)
15 print(s)
KeyError: 100
# pop 随机移除一个元素
s = {1,2,3,4,5,6,7}
d = s.pop()
print(d)
print(s)
1
{2, 3, 4, 5, 6, 7}
# 集合函数
# intersection:交集
# difference:差集
# union:并集
# issubset:检查一个集合是否为另一个子集
# issuperset:检查一个集合是否为另一个超集
s1 = {1,2,3,4,5,6}
s2 = {5,6,7,8,9}
s_1 = s1.intersection(s2)
print(s_1)
s_2 = s1.difference(s2)
print(s_2)
s_3 = s1.issubset(s2)
print(s_3)
s_4 = s1.issuperset(s2)
print(s_4)
{5, 6}
{1, 2, 3, 4}
False
False
# 集合数学操作
s1 = {1,2,3,4,5,6}
s2 = {5,6,7,8,9}
# 以下不支持
s_1 = s1 - s2
print(s_1)
s_2 = s1 + s2
print(s_2)
{1, 2, 3, 4}
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-45-fac787d752ea> in <module>
7 print(s_1)
8
----> 9 s_2 = s1 + s2
10 print(s_2)
TypeError: unsupported operand type(s) for +: 'set' and 'set'
# 创建
s = frozenset()
print(type(s))
print(s)
<class 'frozenset'>
frozenset()
# 字典的创建
# 创建空字典1
d = {}
print(type(d))
print(d)
# 创建空字典2
d = dict()
print(d)
# 创建有值的字典,每一组数据用冒号隔开,每一对键值对用逗号隔开
d = {"one":1, "two":2, "three":3}
print(d)
# 用dict创建有内容字典1
d = dict({"one":1, "two":2, "three":3})
print(d)
# 用dict创建有内字典2
# 利用关键参数
d = dict(one=1, two=2, three=3)
print(d)
#
d = dict( [("one",1), ("two",2), ("three",3)])
print(d)
<class 'dict'>
{}
{}
{'one': 1, 'two': 2, 'three': 3}
{'one': 1, 'two': 2, 'three': 3}
{'one': 1, 'two': 2, 'three': 3}
{'one': 1, 'two': 2, 'three': 3}
# 访问数据
d = {"one":1, "two":2, "three":3}
# 注意访问格式
# 中括号内是键值
print(d["one"])
d["one"] = "eins"
print(d)
# 删除某个操作
# 使用del操作
del d["one"]
print(d)
1
{'one': 'eins', 'two': 2, 'three': 3}
{'two': 2, 'three': 3}
# 成员检测:in,not in
# 成员检测检测时的key内容
d = {"one":1, "two":2, "three":3}
if 2 in d:
print("value")
if "two" in d:
print("key")
if ("two,2") in d:
print("kv")
key
# 遍历在python2 和 3 中区别比较大,代码不通用
# 按key值使用for循环
d = {"one":1, "two":2, "three":3}
# 使用for循环,直接按keu值访问
for k in d:
print(k, d[k])
# 上述代码可以改写如下
for k in d.keys():
print(k, d[k])
# 只访问字典的值
for v in d.values():
print(v)
# 注意以下特殊用法
for k,v in d.items():
print(k, "--", v)
one 1
two 2
three 3
one 1
two 2
three 3
1
2
3
one -- 1
two -- 2
three -- 3
d = {"one":1, "two":2, "three":3}
# 常规字典生成式
dd = {k:v for k,v in d.items()}
print(dd)
# 加限制条件的字典生成式
dd = {k:v for k,v in d.items() if v % 2 == 0}
print(dd)
{'one': 1, 'two': 2, 'three': 3}
{'two': 2}
# 通用函数:len,max,min,dict
# str(字典):用于返回字典的字符串格式
d = {"one":1, "two":2, "three":3}
print(str(d))
{'one': 1, 'two': 2, 'three': 3}
# clear:清空字典
# items:返回字典的键值对组成的元组格式
d = {"one":1, "two":2, "three":3}
i = d.items()
print(type(i))
print(i)
<class 'dict_items'>
dict_items([('one', 1), ('two', 2), ('three', 3)])
# keys:返回字典的键组成的一个结构
k = d.keys()
print(type(k))
print(k)
<class 'dict_keys'>
dict_keys(['one', 'two', 'three'])
# values:同理,一个可迭代的结构
v = d.values()
print(type(v))
print(v)
<class 'dict_values'>
dict_values([1, 2, 3])
# get:根据指定键返回相应的值,好处是,可以生成默认值
d = {"one":1, "two":2, "three":3}
print(d.get("oner"))
# get默认值是None,可以设置
print(d.get("one", 100))
print(d.get("one33", 100))
print(d['on333'])
None
1
100
---------------------------------------------------------------------------
KeyError Traceback (most recent call last)
<ipython-input-86-f8c01a58018e> in <module>
8 print(d.get("one33", 100))
9
---> 10 print(d['on333'])
KeyError: 'on333'
# fromkeys:使用指定的序列作为键,使用一个值作为字典的所有键的值
l = ["eins", "zwei", "dree"]
# 注意fromkeys两个参数的类型
# 注意fromkeys的调用主体
d = dict.fromkeys(l, "hahahahaha")
print(d)
{'eins': 'hahahahaha', 'zwei': 'hahahahaha', 'dree': 'hahahahaha'}
原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。
如有侵权,请联系 cloudcommunity@tencent.com 删除。
原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。
如有侵权,请联系 cloudcommunity@tencent.com 删除。