EasyScreenLive同屏功能组件C#版中如何实现RTSPSERVER中的获取本机IP功能

/// <summary>  
/// 获取当前使用的IP  
/// </summary>  
/// <returns></returns>  
private static string GetLocalIP()
{
  try
     {
       string HostName = Dns.GetHostName(); //得到主机名
       IPHostEntry IpEntry = Dns.GetHostEntry(HostName);
       for (int i = 0; i < IpEntry.AddressList.Length; i++)
          {
            //从IP地址列表中筛选出IPv4类型的IP地址
            //AddressFamily.InterNetwork表示此IP为IPv4,
            //AddressFamily.InterNetworkV6表示此地址为IPv6类型
 if (IpEntry.AddressList[i].AddressFamily == AddressFamily.InterNetwork)
                    {
                        return IpEntry.AddressList[i].ToString();
                    }
            }
                return "";
       }
      catch (Exception ex)
      {
          MessageBox.Show("获取本机IP出错:" + ex.Message);
          return "";
       }
        }
 

serverId0 = CapturePusher.CapturePusherSDK.EasyScreenLive_StartServer(pusherPtr, serverPort, string.Empty, string.Empty, pData, 1);
isServerOpen = serverId0 >= 0; Log(string.Format(“开启RTSP服务: rtsp://{0}:{1}/channel=0 {2}”, GetLocalIP(), serverPort, isServerOpen ? “成功” : “失敗”));