面试题-python3 找出列表中出现的所有连续数字

"""
# 作者-上海悠悠 QQ交流群:717225969
# blog地址 https://www.cnblogs.com/yoyoketang/
判断列表中的数字是否连续
x = [1,2,3,4]
y = [5,6,8,9]
"""
x = [1, 2, 3, 4]

z = []
flag = True
for i in x:
    if len(z) == 0 or z[-1] + 1 == i:
        z.append(i)
    else:
        flag = False
        break
print(flag)

"""
有一个列表a=[1,2,3,8,6,7,5,10,16,98,99,100,101] 不考虑数字的顺序
找出连续的数字
# 作者-上海悠悠 QQ交流群:717225969
# blog地址 https://www.cnblogs.com/yoyoketang/
"""
a = [1,2,3,8,6,7,5,10,16,98,99,100,101]
s = []  # 空栈
for i in sorted(set(a)):
    if len(s) == 0 or s[-1] + 1 == i:
        s.append(i)  # 入栈
    else:
        if len(s) >= 2:
            print(s)
        s = []    # 清空
        s.append(i)  # 入栈
# 最后一轮，需判断下
if len(s) >= 2:
    print(s)

aa = [1, 2, 3, 8, 6, 7, 5, 10, 16, 98, 99, 100, 101]
l1 = []
for x in sorted(set(aa)):
    l1.append(x)
    if x+1 not in aa:
        if len(l1) != 1:
            print(l1)
        l1 = []