【每日一题 lc.160】坚持Leetcode2个月分享

pA:1->2->3->4->5->6->null->9->5->6->null
pB:9->5->6->null->1->2->3->4->5->6->null

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode *getIntersectionNode(ListNode *headA, ListNode *headB) {
        ListNode* p = headA, *q = headB;
        while (p != q) {
            p = p ? p->next : headB;
            q = q ? q->next : headA;
        }
        return p;
    }
};