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社区首页 >专栏 >LeetCode 0057 - Insert Interval

LeetCode 0057 - Insert Interval

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Reck Zhang
发布2021-08-11 10:36:43
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发布2021-08-11 10:36:43
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文章被收录于专栏:Reck Zhang

Insert Interval

Desicription

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).

You may assume that the intervals were initially sorted according to their start times.

Example 1:

Given intervals [1,3],[6,9], insert and merge [2,5] in as [1,5],[6,9].

Example 2:

Given [1,2],[3,5],[6,7],[8,10],[12,16], insert and merge [4,9] in as [1,2],[3,10],[12,16].

This is because the new interval [4,9] overlaps with [3,5],[6,7],[8,10].

Solution

代码语言:javascript
复制
/**
 * Definition for an interval.
 * struct Interval {
 *     int start;
 *     int end;
 *     Interval() : start(0), end(0) {}
 *     Interval(int s, int e) : start(s), end(e) {}
 * };
 */
class Solution {
public:
    vector<Interval> insert(vector<Interval>& intervals, Interval newInterval) {
        vector<Interval> res;
        auto it = intervals.begin();
        for(; it != intervals.end(); it++){
            if(it->start > newInterval.end)
                break;
            else if(it->end < newInterval.start)
                res.push_back(*it);
            else
                newInterval.start = min(newInterval.start, it->start), newInterval.end = max(newInterval.end, it->end);
        }
        res.push_back(newInterval);
        for(; it != intervals.end(); it++)
            res.push_back(*it);
        return res;
    }
};
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目录
  • Insert Interval
    • Desicription
      • Solution
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