Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Example:
Input: "Hello World"
Output: 5
class Solution {
public:
int lengthOfLastWord(string s) {
int len = 0;
for(int i = 0; s[i];){
if(s[i++] != ' ')
len++;
else if(s[i] && s[i] != ' ')
len = 0;
}
return len;
}
};