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社区首页 >专栏 >LeetCode 0068 - Text Justification

LeetCode 0068 - Text Justification

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Reck Zhang
发布2021-08-11 10:49:04
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发布2021-08-11 10:49:04
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文章被收录于专栏:Reck Zhang

Text Justification

Desicription

Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified.

You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces ‘ ‘ when necessary so that each line has exactly L characters.

Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.

For the last line of text, it should be left justified and no extra space is inserted between words.

For example,

words: ["This", "is", "an", "example", "of", "text", "justification."]

L: 16.

Return the formatted lines as:

代码语言:javascript
复制
[
   "This    is    an",
   "example  of text",
   "justification.  "
]

Note: Each word is guaranteed not to exceed L in length.

Solution

代码语言:javascript
复制
class Solution{
  public:
    vector<string> fullJustify(vector<string>& words, int maxWidth){
        vector<string> res;
        for (int i = 0, k, l; i < words.size(); i += k){
            for (k = l = 0; i + k < words.size() && l + words[i + k].size() <= maxWidth - k; k++)
                l += words[i + k].size();
            string tmp = words[i];
            for (int j = 0; j < k - 1; j++){
                if (i + k >= words.size())
                    tmp += " ";
                else
                    tmp += string((maxWidth - l) / (k - 1) + (j < (maxWidth - l) % (k - 1)), ' ');
                tmp += words[i + j + 1];
            }
            tmp += string(maxWidth - tmp.size(), ' ');
            res.push_back(tmp);
        }
        return res;
    }
};
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目录
  • Text Justification
    • Desicription
      • Solution
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