Follow up for problem “Populating Next Right Pointers in Each Node
“.
What if the given tree could be any binary tree? Would your previous solution still work?
Note:
For example, Given the following binary tree,
1
/ \
2 3
/ \ \
4 5 7
After calling your function, the tree should look like:
1 -> NULL
/ \
2 -> 3 -> NULL
/ \ \
4-> 5 -> 7 -> NULL
/**
* Definition for binary tree with next pointer.
* struct TreeLinkNode {
* int val;
* TreeLinkNode *left, *right, *next;
* TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {}
* };
*/
class Solution {
public:
void connect(TreeLinkNode *root) {
TreeLinkNode* cur = root;
TreeLinkNode* nextLevelHead = NULL;
TreeLinkNode* nextLevelPre = NULL;
while(cur != NULL) {
while(cur != NULL) {
if(cur->left != NULL) {
if(nextLevelPre != NULL)
nextLevelPre->next = cur->left;
else
nextLevelHead = cur->left;
nextLevelPre = cur->left;
}
if(cur->right != NULL) {
if(nextLevelPre != NULL)
nextLevelPre->next = cur->right;
else
nextLevelHead = cur->right;
nextLevelPre = cur->right;
}
cur = cur->next;
}
cur = nextLevelHead;
nextLevelHead = NULL;
nextLevelPre = NULL;
}
}
};