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社区首页 >专栏 >LeetCode 0124 - Binary Tree Maximum Path Sum

LeetCode 0124 - Binary Tree Maximum Path Sum

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Reck Zhang
发布2021-08-11 10:56:17
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发布2021-08-11 10:56:17
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文章被收录于专栏:Reck Zhang

Binary Tree Maximum Path Sum

Desicription

Given a binary tree, find the maximum path sum.

For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path must contain at least one node and does not need to go through the root.

For example: Given the below binary tree,

代码语言:javascript
复制
  1
 / \
2   3

Return 6.

Solution

代码语言:javascript
复制
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
private:
    int res = INT_MIN;
    int getSonMax(TreeNode* cur) {
        if(cur == NULL)
            return 0;
        int l = max(0, getSonMax(cur->left));
        int r = max(0, getSonMax(cur->right));
        res = max(res, l + r + cur->val);
        return cur->val + max(l, r);
    }
public:
    int maxPathSum(TreeNode* root) {
        getSonMax(root);
        return res;
    }
};
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目录
  • Binary Tree Maximum Path Sum
    • Desicription
      • Solution
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