前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >LeetCode 0313 - Super Ugly Number

LeetCode 0313 - Super Ugly Number

作者头像
Reck Zhang
发布2021-08-11 11:14:22
2370
发布2021-08-11 11:14:22
举报
文章被收录于专栏:Reck Zhang

Super Ugly Number

Desicription

Write a program to find the nth super ugly number.

Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k.

Example:

代码语言:javascript
复制
Input: n = 12, primes = [2,7,13,19]
Output: 32 
Explanation: [1,2,4,7,8,13,14,16,19,26,28,32] is the sequence of the first 12 
             super ugly numbers given primes = [2,7,13,19] of size 4.

Note:

  • 1 is a super ugly number for any given primes.
  • The given numbers in primes are in ascending order.
  • 0 < k ≤ 100, 0 < n ≤ 106, 0 < primes[i] < 1000.
  • The nth super ugly number is guaranteed to fit in a 32-bit signed integer.

Solution

代码语言:javascript
复制
class Solution {
public:
    int nthSuperUglyNumber(int n, std::vector<int>& primes) {
        auto index = std::vector<int>(primes.size(), 0);
        auto uglys = std::vector<int>(n, INT_MAX);
        uglys[0] = 1;

        for(auto& ugly : uglys) {
            for(int i = 0; i < index.size(); i++) {
                ugly = std::min(ugly, uglys[index[i]] * primes[i]);
            }
            for(int i = 0; i < index.size(); i++) {
                if(ugly == uglys[index[i]] * primes[i]) {
                    index[i]++;
                }
            }
        }

        return uglys[uglys.size() - 1];
    }
};
本文参与 腾讯云自媒体同步曝光计划,分享自作者个人站点/博客。
原始发表:2019-05-14,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体同步曝光计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
目录
  • Super Ugly Number
    • Desicription
      • Solution
      领券
      问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档