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社区首页 >专栏 >LeetCode 0341 - Flatten Nested List Iterator

LeetCode 0341 - Flatten Nested List Iterator

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Reck Zhang
发布2021-08-11 11:20:14
发布2021-08-11 11:20:14
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Flatten Nested List Iterator

Desicription

Given a nested list of integers, implement an iterator to flatten it.

Each element is either an integer, or a list – whose elements may also be integers or other lists.

Example 1:

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Input: [[1,1],2,[1,1]]
Output: [1,1,2,1,1]
Explanation: By calling next repeatedly until hasNext returns false, 
             the order of elements returned by next should be: [1,1,2,1,1].

Example 2:

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Input: [1,[4,[6]]]
Output: [1,4,6]
Explanation: By calling next repeatedly until hasNext returns false, 
             the order of elements returned by next should be: [1,4,6].

Solution

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/**
 * // This is the interface that allows for creating nested lists.
 * // You should not implement it, or speculate about its implementation
 * class NestedInteger {
 *   public:
 *     // Return true if this NestedInteger holds a single integer, rather than a nested list.
 *     bool isInteger() const;
 *
 *     // Return the single integer that this NestedInteger holds, if it holds a single integer
 *     // The result is undefined if this NestedInteger holds a nested list
 *     int getInteger() const;
 *
 *     // Return the nested list that this NestedInteger holds, if it holds a nested list
 *     // The result is undefined if this NestedInteger holds a single integer
 *     const vector<NestedInteger> &getList() const;
 * };
 */
class NestedIterator {
private:
    std::vector<int> integerVector;
    int index;
public:
    explicit NestedIterator(const std::vector<NestedInteger>& nestedList) {
        index = 1;
        integerVector = std::vector<int>(1);
        std::function<void(const std::vector<NestedInteger>& nestedLis)> dfs = [&](const std::vector<NestedInteger>& roots) {
            for(const auto& root : roots) {
                if(root.isInteger()) {
                    integerVector.push_back(root.getInteger());
                } else {
                    dfs(root.getList());
                }
            }
        };
        dfs(nestedList);
    }

    int next() {
        return integerVector[index++];
    }

    bool hasNext() {
        return index <= integerVector.size() - 1;
    }
};

/**
 * Your NestedIterator object will be instantiated and called as such:
 * NestedIterator i(nestedList);
 * while (i.hasNext()) cout << i.next();
 */
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原始发表:2019-06-05,如有侵权请联系 cloudcommunity@tencent.com 删除

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目录
  • Flatten Nested List Iterator
    • Desicription
    • Solution
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