LeetCode 0334 - Increasing Triplet Subsequence

Reck Zhang

发布于 2021-08-11 11:21:53

2720

发布于 2021-08-11 11:21:53

文章被收录于专栏：Reck Zhang

Increasing Triplet Subsequence

Desicription

Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.

Formally the function should:

Return true if there exists i, j, k such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false. Note: Your algorithm should run in O(n) time complexity and O(1) space complexity.

Example 1:

Input: [1,2,3,4,5]
Output: true

Example 2:

Input: [5,4,3,2,1]
Output: false

Solution

class Solution {
public:
    bool increasingTriplet(std::vector<int>& nums) {
        int c1 = INT_MAX;
        int c2 = INT_MAX;
        for(auto num : nums) {
            if(num <= c1) {
                c1 = num;
            } else if(num <= c2) {
                c2 = num;
            } else {
                return true;
            }
        }

        return false;
    }
};

本文参与腾讯云自媒体同步曝光计划，分享自作者个人站点/博客。

原始发表：2019-06-02，如有侵权请联系 cloudcommunity@tencent.com 删除

algorithm