Sword To Offer 056 - 删除链表中重复的结点

/*
struct ListNode {
    int val;
    struct ListNode *next;
    ListNode(int x) :
        val(x), next(NULL) {
    }
};
*/
class Solution {
public:
    ListNode* deleteDuplication(ListNode* pHead) {
        auto newHead = new ListNode(0);
        newHead->next = pHead;
        pHead = newHead;
        auto current = pHead;
        while(current && current->next) {
            auto nextNode = current->next;
            bool reFlag = false;
            while(nextNode->next && nextNode->val == nextNode->next->val) {
                nextNode = nextNode->next;
                reFlag = true;
            }
            if(reFlag) {
                current->next = nextNode->next;
            } else {
                current = current->next;
            }
        }
        return pHead->next;
    }
};