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社区首页 >专栏 >LeetCode 0237 - Delete Node in a Linked List

LeetCode 0237 - Delete Node in a Linked List

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Reck Zhang
发布2021-08-11 12:04:52
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发布2021-08-11 12:04:52
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文章被收录于专栏:Reck Zhang

Delete Node in a Linked List

Desicription

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Given linked list – head = [4,5,1,9], which looks like following:

代码语言:javascript
复制
4 -> 5 -> 1 -> 9

Example 1:

代码语言:javascript
复制
Input: head = [4,5,1,9], node = 5
Output: [4,1,9]
Explanation: You are given the second node with value 5, the linked list
             should become 4 -> 1 -> 9 after calling your function.

Example 2:

代码语言:javascript
复制
Input: head = [4,5,1,9], node = 1
Output: [4,5,9]
Explanation: You are given the third node with value 1, the linked list
             should become 4 -> 5 -> 9 after calling your function.

Note:

  • The linked list will have at least two elements.
  • All of the nodes’ values will be unique.
  • The given node will not be the tail and it will always be a valid node of the linked list.
  • Do not return anything from your function.

Solution

代码语言:javascript
复制
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void deleteNode(ListNode* node) {
        *node = *node->next;
    }
};
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  • Delete Node in a Linked List
    • Desicription
      • Solution
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