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社区首页 >专栏 >LeetCode 0138 - Copy List with Random Pointer

LeetCode 0138 - Copy List with Random Pointer

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Reck Zhang
发布2021-08-11 14:47:42
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发布2021-08-11 14:47:42
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文章被收录于专栏:Reck Zhang

Copy List with Random Pointer

Desicription

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null.

Return a deep copy of the list.

Solution

代码语言:javascript
复制
/**
 * Definition for singly-linked list with a random pointer.
 * struct RandomListNode {
 *     int label;
 *     RandomListNode *next, *random;
 *     RandomListNode(int x) : label(x), next(NULL), random(NULL) {}
 * };
 */
class Solution {
public:
    RandomListNode* copyRandomList(RandomListNode* head) {
        if(head == NULL)
            return NULL;
        for(RandomListNode* l1 = head; l1 != NULL; l1 = l1->next) {
            RandomListNode* l2 = new RandomListNode(l1->label);
            l2->next = l1->random;
            l1->random = l2;
        }
        for(RandomListNode* l1 = head; l1 != NULL; l1 = l1->next) {
            RandomListNode* l2 = l1->random;
            l2->random = l2->next?l2->next->random:NULL;
        }
        RandomListNode* newHead = head->random;
        for(RandomListNode* l1 = head; l1 != NULL; l1 = l1->next) {
            RandomListNode* l2 = l1->random;
            l1->random = l2->next;
            l2->next = l1->next?l1->next->random:NULL;
        }
        return newHead;
    }
};
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  • Copy List with Random Pointer
    • Desicription
      • Solution
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