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社区首页 >专栏 >LeetCode 0178 - Rank Scores

LeetCode 0178 - Rank Scores

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Reck Zhang
发布2021-08-11 14:53:14
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发布2021-08-11 14:53:14
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文章被收录于专栏:Reck ZhangReck Zhang

Rank Scores

Desicription

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no “holes” between ranks.

代码语言:javascript
复制
+----+-------+
| Id | Score |
+----+-------+
| 1  | 3.50  |
| 2  | 3.65  |
| 3  | 4.00  |
| 4  | 3.85  |
| 5  | 4.00  |
| 6  | 3.65  |
+----+-------+

For example, given the above Scores table, your query should generate the following report (order by highest score):

代码语言:javascript
复制
+-------+------+
| Score | Rank |
+-------+------+
| 4.00  | 1    |
| 4.00  | 1    |
| 3.85  | 2    |
| 3.65  | 3    |
| 3.65  | 3    |
| 3.50  | 4    |
+-------+------+

Solution

代码语言:javascript
复制
SELECT
Score,
(SELECT COUNT(*) FROM (SELECT DISTINCT Score s FROM Scores) tmpTable WHERE s >= Score) Rank
FROM Scores
ORDER BY Score DESC
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原始发表:2018-06-04,如有侵权请联系 cloudcommunity@tencent.com 删除

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目录
  • Rank Scores
    • Desicription
      • Solution
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