05 Subtract the Product and Sum of Digits of an Integer

题目

Given an integer number n, return the difference between the product of its digits and the sum of its digits.

Example 1:

Input: n = 234 Output: 15 Explanation: Product of digits = 2 * 3 * 4 = 24 Sum of digits = 2 + 3 + 4 = 9 Result = 24 - 9 = 15

Example 2:

Input: n = 4421 Output: 21 Explanation: Product of digits = 4 * 4 * 2 * 1 = 32 Sum of digits = 4 + 4 + 2 + 1 = 11 Result = 32 - 11 = 21

Constraints:

1 <= n <= 10^5

解析

题目通俗易懂，不多做解释。 解题关键就在于获取到一个数的每位数—>取余10再除以10，重复操作即可 如123 123%10=3 123/10=12 12%10=2 12/10=1 1%10=1

答案

class Solution {
    public int subtractProductAndSum(int n) {
        int product=1;
        int sum=0;
        while(n>0){
            int tmp=n%10;
            product*=tmp;
            sum+=tmp;
            n/=10;
        }
        return product-sum;
    }
}

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评论区似乎没有其他更好的解法。