给你一个下标从 0 开始的 8 x 8 网格 board ,其中 board[r][c]
表示游戏棋盘上的格子 (r, c)
。
棋盘上空格用 '.'
表示,白色格子用 'W'
表示,黑色格子用 'B'
表示。
游戏中每次操作步骤为:选择一个空格子,将它变成你正在执行的颜色(要么白色,要么黑色)。 但是,合法 操作必须满足:涂色后这个格子是 好线段的一个端点 (好线段可以是水平的,竖直的或者是对角线)。
好线段 指的是一个包含 三个或者更多格子(包含端点格子)的线段,线段两个端点格子为 同一种颜色 ,且中间剩余格子的颜色都为 另一种颜色 (线段上不能有任何空格子)。
你可以在下图找到好线段的例子:
给你两个整数 rMove 和 cMove 以及一个字符 color ,表示你正在执行操作的颜色(白或者黑),如果将格子 (rMove, cMove) 变成颜色 color 后,是一个 合法 操作,那么返回 true ,如果不是合法操作返回 false 。
示例 1:
输入:board = [
[".",".",".","B",".",".",".","."],
[".",".",".","W",".",".",".","."],
[".",".",".","W",".",".",".","."],
[".",".",".","W",".",".",".","."],
["W","B","B",".","W","W","W","B"],
[".",".",".","B",".",".",".","."],
[".",".",".","B",".",".",".","."],
[".",".",".","W",".",".",".","."]],
rMove = 4, cMove = 3, color = "B"
输出:true
解释:'.','W' 和 'B' 分别用颜色蓝色,白色和黑色表示。
格子 (rMove, cMove) 用 'X' 标记。
以选中格子为端点的两个好线段在上图中用红色矩形标注出来了。
示例 2:
输入:board = [
[".",".",".",".",".",".",".","."],
[".","B",".",".","W",".",".","."],
[".",".","W",".",".",".",".","."],
[".",".",".","W","B",".",".","."],
[".",".",".",".",".",".",".","."],
[".",".",".",".","B","W",".","."],
[".",".",".",".",".",".","W","."],
[".",".",".",".",".",".",".","B"]],
rMove = 4, cMove = 4, color = "W"
输出:false
解释:虽然选中格子涂色后,棋盘上产生了好线段,
但选中格子是作为中间格子,没有产生以选中格子为端点的好线段。
提示:
board.length == board[r].length == 8
0 <= rMove, cMove < 8
board[rMove][cMove] == '.'
color 要么是 'B' 要么是 'W' 。
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/check-if-move-is-legal 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
class Solution {
public:
bool checkMove(vector<vector<char>>& board, int rMove, int cMove, char color) {
vector<vector<int>> dir = {{1,0},{0,1},{-1,0},{0,-1},{1,1},{1,-1},{-1,1},{-1,-1}};
for(int i = 0; i < 8; ++i)
{
bool revColor = false;
int x = rMove, y = cMove;
while(inside(x+dir[i][0], y+dir[i][1]))
{
if(board[x+dir[i][0]][y+dir[i][1]]=='.') // 遇到空格
{
break;
}
if(board[x+dir[i][0]][y+dir[i][1]] != color) //与起点相反的颜色
revColor = true;
else // 起点相同的颜色
{
if (revColor == true)
return true;
break;
}
x += dir[i][0];
y += dir[i][1];
}
}
return false;
}
bool inside(int x, int y)
{
return x>=0 && x<8 && y>=0 && y<8;
}
};
4 ms 10.9 MB C++
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