前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >python 接口 、继承、重载运算符

python 接口 、继承、重载运算符

作者头像
Michael阿明
发布2021-09-06 11:40:42
3470
发布2021-09-06 11:40:42
举报
文章被收录于专栏:Michael阿明学习之路

文章目录

learn from 《流畅的python》

1. 序列__getitem__

如果没有 __iter____contains__ 方法, Python 会调用 __getitem__ 方法, 设法让 迭代 和 in 运算符可用

代码语言:javascript
复制
class Foo:
    def __getitem__(self, pos):
        return range(0, 30, 10)[pos]


f = Foo()
print(f[1])  # 10
for i in f:
    print(i)  # 0, 10, 20
# 如果没有 __iter__ 和 __contains__ 方法,
# Python 会调用 __getitem__ 方法,
# 设法让迭代和 in 运算符可用

2. __setitem__

代码语言:javascript
复制
import collections

Card = collections.namedtuple('Card', ['rank', 'suit'])


class FrenchDeck:
    ranks = [str(n) for n in range(2, 11)] + list('JQKA')
    suits = 'spades diamonds clubs hearts'.split()

    def __init__(self):
        self._cards = [Card(rank, suit) for suit in self.suits for rank in self.ranks]

    def __len__(self):
        return len(self._cards)

    def __getitem__(self, position):
        return self._cards[position]
	
	def __str__(self):
        return ",".join(str(i) for i in self._cards)

from random import shuffle

deck = FrenchDeck()
print(str(deck))
# Card(rank='2', suit='spades'),Card(rank='3', suit='spades'),Card(rank='4', suit='spades'),Card(rank='5', suit='spades'),Card(rank='6', suit='spades'),Card(rank='7', suit='spades'),Card(rank='8', suit='spades'),Card(rank='9', suit='spades'),Card(rank='10', suit='spades'),Card(rank='J', suit='spades'),Card(rank='Q', suit='spades'),Card(rank='K', suit='spades'),Card(rank='A', suit='spades'),Card(rank='2', suit='diamonds'),Card(rank='3', suit='diamonds'),Card(rank='4', suit='diamonds'),Card(rank='5', suit='diamonds'),Card(rank='6', suit='diamonds'),Card(rank='7', suit='diamonds'),Card(rank='8', suit='diamonds'),Card(rank='9', suit='diamonds'),Card(rank='10', suit='diamonds'),Card(rank='J', suit='diamonds'),Card(rank='Q', suit='diamonds'),Card(rank='K', suit='diamonds'),Card(rank='A', suit='diamonds'),Card(rank='2', suit='clubs'),Card(rank='3', suit='clubs'),Card(rank='4', suit='clubs'),Card(rank='5', suit='clubs'),Card(rank='6', suit='clubs'),Card(rank='7', suit='clubs'),Card(rank='8', suit='clubs'),Card(rank='9', suit='clubs'),Card(rank='10', suit='clubs'),Card(rank='J', suit='clubs'),Card(rank='Q', suit='clubs'),Card(rank='K', suit='clubs'),Card(rank='A', suit='clubs'),Card(rank='2', suit='hearts'),Card(rank='3', suit='hearts'),Card(rank='4', suit='hearts'),Card(rank='5', suit='hearts'),Card(rank='6', suit='hearts'),Card(rank='7', suit='hearts'),Card(rank='8', suit='hearts'),Card(rank='9', suit='hearts'),Card(rank='10', suit='hearts'),Card(rank='J', suit='hearts'),Card(rank='Q', suit='hearts'),Card(rank='K', suit='hearts'),Card(rank='A', suit='hearts')
shuffle(deck)  # TypeError: 'FrenchDeck' object does not support item assignment
  • 加入__setitem__
代码语言:javascript
复制
    def __setitem__(self, key, value):
        self._cards[key] = value
代码语言:javascript
复制
shuffle(deck) 
print(str(deck))
# 牌被随机打乱了
# Card(rank='6', suit='hearts'),Card(rank='2', suit='spades'),Card(rank='3', suit='hearts'),Card(rank='A', suit='clubs'),Card(rank='7', suit='clubs'),Card(rank='Q', suit='diamonds'),Card(rank='5', suit='hearts'),Card(rank='6', suit='spades'),Card(rank='5', suit='diamonds'),Card(rank='8', suit='diamonds'),Card(rank='K', suit='hearts'),Card(rank='Q', suit='hearts'),Card(rank='8', suit='hearts'),Card(rank='3', suit='diamonds'),Card(rank='Q', suit='clubs'),Card(rank='A', suit='diamonds'),Card(rank='9', suit='hearts'),Card(rank='7', suit='diamonds'),Card(rank='A', suit='spades'),Card(rank='J', suit='hearts'),Card(rank='3', suit='clubs'),Card(rank='4', suit='hearts'),Card(rank='Q', suit='spades'),Card(rank='10', suit='diamonds'),Card(rank='10', suit='hearts'),Card(rank='K', suit='diamonds'),Card(rank='2', suit='diamonds'),Card(rank='4', suit='spades'),Card(rank='3', suit='spades'),Card(rank='7', suit='hearts'),Card(rank='9', suit='clubs'),Card(rank='J', suit='clubs'),Card(rank='J', suit='diamonds'),Card(rank='10', suit='spades'),Card(rank='4', suit='diamonds'),Card(rank='7', suit='spades'),Card(rank='9', suit='diamonds'),Card(rank='2', suit='hearts'),Card(rank='6', suit='clubs'),Card(rank='K', suit='clubs'),Card(rank='4', suit='clubs'),Card(rank='A', suit='hearts'),Card(rank='K', suit='spades'),Card(rank='2', suit='clubs'),Card(rank='J', suit='spades'),Card(rank='8', suit='spades'),Card(rank='5', suit='spades'),Card(rank='9', suit='spades'),Card(rank='10', suit='clubs'),Card(rank='8', suit='clubs'),Card(rank='6', suit='diamonds'),Card(rank='5', suit='clubs')

或者 在类外打补丁 FrenchDeck.__setitem__ = 函数

代码语言:javascript
复制
def set_card(deck, position, card):
    deck._cards[position] = card


FrenchDeck.__setitem__ = set_card

3. 抽象基类

代码语言:javascript
复制
class Test:
    def __len__(self):
        return 24


from collections import abc

print(isinstance(Test(), abc.Sized)) # True

只要实现了 __len__() 方法,就可以被 abc.Sized 识别为子类

4. 不要直接子类化内置类型

代码语言:javascript
复制
class AnswerDict(dict):
    def __getitem__(self, key):
        return 24


ad = AnswerDict(a="good")
print(ad['a'])  # 24
d = {}
d.update(ad)
print(d['a'])  # good
print(ad)  # {'a': 'good'}
print(d)  # {'a': 'good'}

直接子类化内置类型(如 dict、liststr)容易出错, 因为 内置类型的方法 通常会 忽略用户覆盖的方法。 不要子类化内置 类型,用户自己定义的类 应该继承 collections 模块 中的类,例如 UserDict、UserListUserString,这些类做了特殊设计,因 此易于扩展

代码语言:javascript
复制
import collections


class AnswerDict2(collections.UserDict):
    def __getitem__(self, key):
        return 24
ad = AnswerDict2(a="good")
print(ad['a'])  # 24
d = {}
d.update(ad)
print(d['a'])  # 24
print(ad)  # {'a': 'good'}
print(d)  # {'a': 24}

5. 继承顺序

  • 多重继承的同名方法调用,根据类的 __mro__ 属性顺次在类中查找
  • 推荐使用 super() 函数

6. 重载运算符

在这里插入图片描述
在这里插入图片描述

不可变类型,,一定不能实现就地特殊方法 __iadd__等增量赋值特殊方法 必须返回 self

本文参与 腾讯云自媒体同步曝光计划,分享自作者个人站点/博客。
原始发表:2021/08/17 ,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体同步曝光计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
目录
  • 文章目录
  • 1. 序列__getitem__
  • 2. __setitem__
  • 3. 抽象基类
  • 4. 不要直接子类化内置类型
  • 5. 继承顺序
  • 6. 重载运算符
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档