
两维同时升序(18%beat,约1400ms)class Solution {
public:
static bool cmp(vector<int>& a, vector<int>& b) {
if (a[0] == b[0]) return a[1] < b[1];
return a[0] < b[0];
}
int maxEnvelopes(vector<vector<int>>& envelopes) {
sort(envelopes.begin(), envelopes.end(), cmp);
int size = envelopes.size();
vector<int> dp(size + 1, 1);
int len = 0;
for (int i = 0; i < size; i++) {
for (int j = 0; j < i; j++)
if (envelopes[j][0] < envelopes[i][0] && envelopes[j][1] < envelopes[i][1])
dp[i] = max(dp[i], dp[j] + 1);
len = max(len, dp[i]);
}
return len;
}
第一维升序,第二维降序,仅按第二维进行标准最长递增子序列解决(54%beat,约1000ms)class Solution {
public:
static bool cmp(vector<int>& a, vector<int>& b) {
if (a[0] == b[0]) return a[1] > b[1];
return a[0] < b[0];
}
int maxEnvelopes(vector<vector<int>>& envelopes) {
sort(envelopes.begin(), envelopes.end(), cmp);
int size = envelopes.size();
vector<int> dp(size + 1, 1);
int len = 0;
for (int i = 0; i < size; i++) {
for (int j = 0; j < i; j++)
if (envelopes[j][1] < envelopes[i][1])
dp[i] = max(dp[i], dp[j] + 1);
len = max(len, dp[i]);
}
return len;
}
};