Leetcode|7. 整数反转

class Solution {
public:
    int reverse(int x) {
        long a = 0;
        while (x / 10 != 0 || x % 10 != 0) {
            // 比如从123中取出2，则a = 3 * 10 + 2 = 32
            a = a * 10 + x % 10;
            x /= 10;
            // 保证在int范围内
            if (a < INT_MIN || a > INT_MAX) return 0;
        }
        return a;
    }
};