-- 方法一
select m.*,@r :=@r + 1 as rank
from mian62 m,(select @r := 0) r
order by score desc;
-- 方法二
set @r=0;
select m.*,@r :=@r + 1 as rank
from mian62 m
order by score desc;
效果如下:
-- 方法一
select c.sid,c.name,c.score,c.rank
from
(
select m.*,
@c:=if(@p=score,@c,@r) as rank,
@p:=score,
@r:=@r+1
from mian62 m,(select @p:=0,@r:=1,@c:=0)r
order by score desc
)c
-- 方法二
set @p=0;
set @r=1;
set @c=0;
select c.sid,c.name,c.score,c.rank
from
(
select m.*,
@c:=if(@p=score,@c,@r) as rank,
@p:=score,
@r:=@r+1
from mian62 m
order by score desc
)c
效果如下:
-- 方法一
select c.sid,c.name,c.score,c.rank
from
(
select m.*,
@c:=if(@p=score,@c,@r) as rank,
@p:=score,
@r:=@r+1
from mian62 m,(select @p:=0,@r:=1,@c:=0)r
order by score desc
)c
-- 方法二
set @p=0;
set @r=1;
set @c=0;
select c.sid,c.name,c.score,c.rank
from
(
select m.*,
@c:=if(@p=score,@c,@r) as rank,
@p:=score,
@r:=@r+1
from mian62 m
order by score desc
)c
效果如下:
select a.sid,a.name,a.subject,a.score,a.rank
from
(
select m.*,
if(@p=subject,@r:=@r+1,@r:=1) as rank,
@p:=subject
from mian62 m,(select @p:=0,@r:=0)r
order by subject,score desc
)a;
效果如下:
-- 为了体现效果,修改其中一条数据;
update mian62 set score=58 where name="张三" and subject="化学";
-- 本题实现代码如下:
select a.sid,a.name,a.subject,a.score,a.rank
from
(
select *,
if(@p=subject,
case
when @s=score then @r
when @s:=score then @r:=@r+1
end,
@r:=1 ) as rank,
@p:=subject,
@s:=score
from mian62 m,(select @p:=0,@s:=0,@r:=0)r
order by subject,score
)a;
效果如下: