MySQL 数据库show processlist where条件筛选报错解决方法，[Code: 1064, SQL State: 42000] You have an error in your

-- 筛选报错
show processlist where user = 'root';
-- 筛选可用
select * from information_schema.processlist where user = 'root';

报错信息如下： 据说是因为 bug，官方还专门声明过。 [Code: 1064, SQL State: 42000] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where user = 'root'' at line 1 show processlist 和 select * from information_schema.processlist 的查询结果是一样的，用后面的方法查询就好了。 运行效果图：