前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >Leetcode 题目解析之 Two Sum

Leetcode 题目解析之 Two Sum

原创
作者头像
ruochen
修改2022-01-08 14:42:41
1.3K0
修改2022-01-08 14:42:41
举报

Given an array of integers, find two numbers such that they add up to a specific target number.

The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.

You may assume that each input would have exactly one solution.

Input: numbers={2, 7, 11, 15}, target=9

Output: index1=1, index2=2

代码语言:txt
复制
    public int[] twoSum(int[] nums, int target) {
        if (nums == null || nums.length <= 1) {
            return new int[2];
        }
        Map<Integer, Integer> map = new HashMap<Integer, Integer>();
        // key = target - nums[i], just one solution
        for (int i = 0; i < nums.length; i++) {
            map.put(target - nums[i], i);
        }
        for (int i = 0; i < nums.length; i++) {
            Integer v = map.get(nums[i]);
            // can't use itself
            if (v != null && v != i) {
                return new int[] { i + 1, v + 1 };
            }
        }
        return null;
    }

原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。

如有侵权,请联系 cloudcommunity@tencent.com 删除。

原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。

如有侵权,请联系 cloudcommunity@tencent.com 删除。

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档