前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >Leetcode 题目解析之 Find Peak Element

Leetcode 题目解析之 Find Peak Element

原创
作者头像
ruochen
发布2022-01-08 14:54:24
1.3K0
发布2022-01-08 14:54:24
举报

A peak element is an element that is greater than its neighbors.

Given an input array where numi ≠ numi+1, find a peak element and return its index.

The array may contain multiple peaks, in that case return the index to any one of the peaks is fine.

You may imagine that num-1 = numn = -∞.

For example, in array 1, 2, 3, 1, 3 is a peak element and your function should return the index number 2.

Note:

Your solution should be in logarithmic complexity.

Credits:

Special thanks to @ts for adding this problem and creating all test cases.

代码语言:txt
复制
    public int findPeakElement(int[] nums) {
        int low = 0;
        int high = nums.length - 1;
        while (low < high) {
            int mid = low + (high - low) / 2;
            if (nums[mid] > nums[mid + 1]) {
                high = mid;
            } else {
                low = mid + 1;
            }
        }
        return low;
    }

原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。

如有侵权,请联系 cloudcommunity@tencent.com 删除。

原创声明:本文系作者授权腾讯云开发者社区发表,未经许可,不得转载。

如有侵权,请联系 cloudcommunity@tencent.com 删除。

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档