问题来源:jieba分词后对满足条件的数据进行【多标签标记】
示例代码:
label=[1,2,3,4,5]
df['分词']=[xx,xx,xx,xx,xx]
df['标签’]=df['分词'].apply(lambda x: 0 if len(set(x)&set(label))==0 else 1)
#&表示交集
a = [1,2,3,4,5,6]
b = [2,4,6,7]
c=[7,8,9,10]
set(b) & set(a)
len(set(c) & set(a))
#交集len长度==0,即:交集为空集,不属于该标签
#其他集合运算:
a<b
a<=b
# a是否包含b,<= 则表示是否是子集
集合相关资料链接: ① https://www.jb51.net/article/153287.htm ②https://www.cnblogs.com/zhaoyingjie/p/8631369.html ③ https://www.jb51.net/article/153287.htm