find
与index
函数string.index(item)
-> item
:查询个数的元素,返回索引位置string.find(item)
-> item
:查询个数的元素,返回索引位置find
如果获取不到,返回-1
index
如果获取不到,直接报错
list1 = [1, 2, 3, 4, 2]
print(list1.index(2))
# coding:utf-8
name = 'dewei'
temp = []
temp.extend(name)
# temp.append(name[0])
# temp.append(name[1])
# temp.append(name[2])
# temp.append(name[3])
# temp.append(name[4])
print(temp)
temp.reverse()
print(temp)
# new_name = '%s%s%s%s%s' % (temp[0], temp[1], temp[2], temp[3], temp[4])
new_name = name[::-1]
print(new_name)
print(new_name)
result = new_name.find('iew')
# result = new_name.index('iew')
print(result)