集合
是否包含相同的元素 , 如果没有返回True
, 否则返回False
没有
才返回Truea_set.isdisjoint(b_set)
b_set
: 与当前集合用来判断的集合True
或False
# coding:utf-8
company_not_allow = {'女', '喝酒', '抽烟', '睡懒觉'}
one_player = {'男', '跑步', '朝气', '喝酒'}
two_player = {'女', '生活规律', '跆拳道'}
three_player = {'男', '太极拳'}
four_player = {'男', '空手道', '年轻'}
print(company_not_allow.isdisjoint(one_player))
print(company_not_allow.isdisjoint(two_player))
print(company_not_allow.isdisjoint(three_player))
print(company_not_allow.isdisjoint(four_player))