C语言实例：统计字符串中英文字母、空格、数字和其它字符的个数

/**
 * Created by 冲哥 on 2021/3/17.
 * 统计出字符串中英文字母、空格、数字和其它字符的个数。
 */
#include<stdio.h>
int main()
{
    char ch;
    int letter_num=0;
    int space_num=0;
    int digit_num=0;
    int other_num=0;
    printf("请输入字符串：\n");
    while((ch=getchar())!='\n')
    {
        if(ch>='a'&&ch<='z'||ch>='A'&&ch<='Z')
            letter_num++;
        else if(ch==' ')
            space_num++;
        else if(ch>='0'&&ch<='9')
            digit_num++;
        else
            other_num++;
    }
    printf("您所输入的字符串中:英文字母有%d个，空格有%d个，数字有%d个，剩余其他字符%d个\n",letter_num,space_num,digit_num,other_num);
    return 0;
}