js与H5 canvas实现动态旋转圣诞树 效果图:
源代码
<canvas id="c" height="356" width="446">
<script>
var collapsed = true;
function toggle() {
var fs = top.document.getElementsByTagName('frameset')[0];
var f = fs.getElementsByTagName('frame');
if (collapsed) {
fs.rows = '250px,*';
fs.noResize = false;
f[0].noResize = false;
f[1].noResize = false;
}
else {
fs.rows = '30px,*';
fs.noResize = true;
f[0].noResize = true;
f[1].noResize = true;
}
collapsed = !collapsed;
}
</script>
<script>
var b = document.body;
var c = document.getElementsByTagName('canvas')[0];
var a = c.getContext('2d');
document.body.clientWidth;
</script>
<script>
M = Math;
Q = M.random; J = [];
U = 16;
T = M.sin;
E = M.sqrt;
for (O = k = 0; x = z = j = i = k < 200;)
with (M[k] = k ? c.cloneNode(0) : c) {
width = height = k ? 32 : W = 446;
with (getContext('2d'))
if (k > 10 | !k)
for (
font = '60px Impact',
V = 'rgba('; I = i * U, fillStyle = k ? k == 13 ? V + '205,205,215,.15)' :
V + (147 + I) + ',' + (k % 2 ? 128 + I : 0) + ',' + I + ',.5)' : '#cca', i < 7;)
beginPath(fill(arc(U - i / 3, 24 - i / 2, k == 13 ? 4 - (i++) / 2 : 8 - i++, 0, M.PI * 2, 1)));
else for (;
x = T(i),
y = Q() * 2 - 1,
D = x * x + y * y,
B = E(D - x / .9 - 1.5 * y + 1),
R = 67 * (B + 1) * (L = k / 9 + .8) >> 1,
i++ < W;
)
if (D < 1)
beginPath(strokeStyle = V + R + ',' + (R + B * L >> 0) + ',40,.1)'),
moveTo(U + x * 8, U + y * 8),
lineTo(U + x * U, U + y * U),
stroke();
for (
y = H = k + E(k++) * 25,
R = Q() * W;
P = 3, j < H;)
J[O++] = [
x += T(R) * P + Q() * 6 - 3, y += Q() * U - 8,
z += T(R - 11) * P + Q() * 6 - 3,
j / H * 20 + ((j += U) > H & Q() > .8 ? Q(P = 9) * 4 : 0) >> 1]
}
setInterval(function G(m, l) {
A = T(D - 11);
if (l)
return (
m[2] - l[2]) * A + (l[0] - m[0]) * T(D);
a.clearRect(0, 0, W, W);
J.sort(G);
for (
i = 0;
L = J[i++];
a.drawImage(M[L[3] + 1], 207 + L[0] * A + L[2] * T(D) >> 0, L[1] >> 1)) {
if (i == 2e3)
a.fillText
('Happy Christmas!', U, 345);
if (!(i % 7))
a.drawImage(M[13],
((157 * (i * i) + T(D * 5 + i * i) * 5) % W) >> 0,
((113 * i + (D * i) / 60) % (290 + i / 99)) >> 0);
}
D += .02
}, 1)
</script>