MongoDB入门实操《下篇》
1、MongoDB 高级操作
数据是随意构建的，大家在练习时可以自己创建，现有的数据为：
> db.test.find()
{ "_id" : ObjectId("5eecc55ec2e3725b5715931b"), "name" : "tony", "age" : 33, "job" : "tester" }
{ "_id" : ObjectId("5eecc5a3c2e3725b5715931c"), "name" : "tom", "age" : 29, "job" : "developer" }
{ "_id" : ObjectId("5eeccc7b613abf5d90d640a2"), "name" : "kim", "age" : 39, "job" : "developer" }
{ "_id" : ObjectId("5eeccd88613abf5d90d640a3"), "name" : "jim", "age" : "39", "job" : "developer" }
{ "_id" : ObjectId("5ef74025613abf5d90d640a4"), "name" : "jeffy", "age" : 40, "job" : "developer" }
{ "_id" : ObjectId("5ef74035613abf5d90d640a5"), "name" : "jeee", "age" : 35, "job" : "developer" }
{ "_id" : ObjectId("5ef7534a613abf5d90d640a6"), "name" : "jeee", "age" : 35, "job" : [ "developer", "tester" ] }
{ "_id" : ObjectId("5ef75351613abf5d90d640a7"), "name" : "jeee", "age" : 35, "job" : [ "developer", "pm" ] }
{ "_id" : ObjectId("5ef7535d613abf5d90d640a8"), "name" : "jeee", "age" : 35, "job" : [ "tester", "pm" ] }
{ "_id" : ObjectId("5ef756d2613abf5d90d640a9"), "name" : { "last" : "jeee", "first" : "tony" }, "age" : 35, "job" : [ "tester", "pm" ] }
{ "_id" : ObjectId("5ef75e54613abf5d90d640aa"), "results" : [ { "item" : "a", "qty" : 26, "tags" : [ "blank", "red" ], "dim_cm" : [ 1, 10 ] }, { "item" : "a", "qty" : 27, "tags" : [ "blank", "red" ], "dim_cm" : [ 15, 30 ] }, { "item" : "a", "qty" : 28, "tags" : [ "blank", "red" ], "dim_cm" : [ 50, 70 ] }, { "item" : "b", "qty" : 27, "tags" : [ "blank", "red" ], "dim_cm" : [ 80, 90 ] } ] }2、$all匹配所有
> db.test.find({job: {$all : ["pm", "tester"]}})// 对数组的查询, 字段job中，既包含"pm",又包含"tester"的纪录
{ "_id" : ObjectId("5ef7535d613abf5d90d640a8"), "name" : "jeee", "age" : 35, "job" : [ "tester", "pm" ] }3、$size数组元素个数
> db.test.find({"job" : {"$size" : 2}}) // 对数组的查询, 查询数组元素个数是3的记录，$size前面无法和其他的操作符复合使用
{ "_id" : ObjectId("5ef7534a613abf5d90d640a6"), "name" : "jeee", "age" : 35, "job" : [ "developer", "tester" ] }
{ "_id" : ObjectId("5ef75351613abf5d90d640a7"), "name" : "jeee", "age" : 35, "job" : [ "developer", "pm" ] }
{ "_id" : ObjectId("5ef7535d613abf5d90d640a8"), "name" : "jeee", "age" : 35, "job" : [ "tester", "pm" ] }4、$exists判断字段是否存在
> db.test.find({age: {$exists: false}}) #查询不存在age 字段的记录，如果为true 表示存在5、$regex正则表达式匹配
> db.test.find({name: {$regex: /^t.*/}}) #查询name是以t 开头的记录
{ "_id" : ObjectId("5eecc55ec2e3725b5715931b"), "name" : "tony", "age" : 33, "job" : "tester" }
{ "_id" : ObjectId("5eecc5a3c2e3725b5715931c"), "name" : "tom", "age" : 29, "job" : "developer" }6、嵌套查询
> db.test.find({"name.last":"jeee"})
{ "_id" : ObjectId("5ef756d2613abf5d90d640a9"), "name" : { "last" : "jeee", "first" : "tony" }, "age" : 35, "job" : [ "tester", "pm" ] }7、聚合查询操作aggregate() 之sum求和
> db.test.aggregate([{$group : {_id: "$name",num_tutorial : {$sum: "$age"}}}])
{ "_id" : "tony", "num_tutorial" : 33 }
{ "_id" : "tom", "num_tutorial" : 29 }
{ "_id" : "jeffy", "num_tutorial" : 40 }
{ "_id" : "jeee", "num_tutorial" : 140 }
{ "_id" : { "last" : "jeee", "first" : "tony" }, "num_tutorial" : 35 }
{ "_id" : "kim", "num_tutorial" : 39 }
{ "_id" : "jim", "num_tutorial" : 0 }
相当于mysql 的
select name, count(*) from test group by name8、聚合查询操作aggregate() 之max求最大值
> db.test.aggregate([{$group : {_id: "$name",num_tutorial : {$max: "$age"}}}])9、聚合查询操作aggregate() 之min求最小值
> db.test.aggregate([{$group : {_id: "$name",num_tutorial : {$min: "$age"}}}])10、聚合查询操作aggregate() 之avg求平均值
> db.test.aggregate([{$group : {_id: "$name",num_tutorial : {$min: "$age"}}}])11、$elemMatch内嵌文档查询匹配
> db.test.find({},{ results: { $elemMatch: { "item":"b","qty":27}},_id:0})
{ "results" : [ { "item" : "b", "qty" : 27, "tags" : [ "blank", "red" ], "dim_cm" : [ 80, 90 ] } ] }Tips：
- 数组中元素要是内嵌文档。
- 如果多个元素匹配$elemMatch条件，操作符返回数组中第一个匹配条件的元素。
12、$where 的妙用
> db.test.find({$where: "this.age > 35"})
{ "_id" : ObjectId("5eeccc7b613abf5d90d640a2"), "name" : "kim", "age" : 39, "job" : "developer" }
{ "_id" : ObjectId("5eeccd88613abf5d90d640a3"), "name" : "jim", "age" : "39", "job" : "developer" }
{ "_id" : ObjectId("5ef74025613abf5d90d640a4"), "name" : "jeffy", "age" : 40, "job" : "developer" }友情提示：“无量测试之道”原创著作，欢迎关注交流，禁止第三方不显示文章来源时转载。
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原始发表：2020-07-01，如有侵权请联系 cloudcommunity@tencent.com 删除
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