解析JSON字符串并添加到数据库中(超简单)

掉发的小王

发布于 2022-07-11 15:22:05

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发布于 2022-07-11 15:22:05

文章被收录于专栏：小王知识分享小王知识分享

一、需求:

我们在开发中也会遇到要我们把json格式数据解析好,然后保存到数据库中.方式方法有很多,小编觉得使用fastjson,最容易实现.

二、依赖准备

	<dependency>
		<groupId>com.alibaba</groupId>
		<artifactId>fastjson</artifactId>
		<version>1.2.69</version>
	</dependency>

三、JSON字符串准备

[
  {
    "id": "155",
    "name": "小米",
    "state": "A",
    "createTime": "2021-08-25"
  },
  {
    "id": "105",
    "name": "小明",
    "state": "B",
    "createTime": "2021-08-25"
  },
  {
    "id": "115",
    "name": "小红",
    "state": "B",
    "createTime": "2021-08-25"
  }
]

四、代码展示

public void jsonToSql(){

        //准备要解析的json字符串
        String json = "[\n" +
                "  {\n" +
                "    \"id\": \"155\",\n" +
                "    \"name\": \"小米\",\n" +
                "    \"state\": \"A\",\n" +
                "    \"createTime\": \"2021-08-25\"\n" +
                "  },\n" +
                "  {\n" +
                "    \"id\": \"105\",\n" +
                "    \"name\": \"小明\",\n" +
                "    \"state\": \"B\",\n" +
                "    \"createTime\": \"2021-08-25\"\n" +
                "  },\n" +
                "  {\n" +
                "    \"id\": \"115\",\n" +
                "    \"name\": \"小红\",\n" +
                "    \"state\": \"B\",\n" +
                "    \"createTime\": \"2021-08-25\"\n" +
                "  }\n" +
                "]";
        //2.将字符串转成list集合
        List<Test> list = JSONObject.parseArray(json, Test.class);

        //3.保存到数据库 ---这里使用mybatis-plus
        list.forEach(x -> testMapper.insert(x));
        //4.我们直接打印集合看看映射对不对
        list.forEach(x -> System.out.println(x));
    }